Thursday, 19 October 2017

Closure... My Maths Classroom

Direct LINK to the survey

[Updated: 21 October 2017]
Click HERE to learn what your classmates shared about their learning experiences in the class :)


Responses to selected questions will be shared via the Google Classroom after today.
You will receive an email alert when it is 'delivered' :)



Saturday, 7 October 2017

Revision: SST 2016 Maths S1 Paper 2 Q4b

There are 2 ways to find xy :

Method 1: (as shown in the suggested solution document, in GoogleSite)
It uses the special products (or algebraic identities) to solve.
Note that we did not need to find x or y value in this method.




Method 2:

In this method, we attempt to solve 2 simple simultaneous equations to find out the values of x and y.
With this, we find xy.




Some of you actually use "Guess and Check" method, where you try to list down possible pairs of integers that can be add together to give 7, followed by check using the other equation. 
Do NOT use this method as it opens up many possibilities which would not worth the time to check one by one.




Revision: SST 2016 Maths S1 Paper 2 Q6

One strategy to solve this problem is to write down and organise the information available.
From there, try to pull the information together to form an equation to solve for the unknowns.





Revision: SST 2016 Maths S1 Paper 2 Q7

Given the speed of the following:

  • Adam     160 m/min
  • Bernard     120 m/min

Strategy: Put all information in a diagram and draw 'relationships' (with reference to the speed-time-distance formula) to form equations



Since we do not know the distance for the race, let it be d metres.
Since we are not given the time taken by Adam to complete the race, let the time taken be t minutes.
The 2nd diagram shows the position of Adam, Bernard and Charlie at t minutes.
Hence, what's common for all three boys is the duration, t minutes.

Using the formula, Distance = Speed x Time



With this, we know that distance covered by Charlie (at t min) = 800 m - 250 m = 550

Substitute d = 550 into first equation (i.e. time taken by Adam), we have
Time taken, t = 800 ÷ 150 = 5 minutes

Hence, Charlie's speed
= Distance covered/ Time taken
= 550 m ÷ 5 min 
= 110 m/min     (Ans)

Note: There are other 'shortcuts' to solve the problem. However, the above will give you an idea how to solve the unknown(s) systematically using the known relationships for speed-time-distance.

Revision: SST 2016 Maths S1 Paper 2 Q8

Watch the video clip (no sound) to understand the diagram


(i) Since the length of the paper is 30 cm, from the diagram, we note that
Height of letter in terms of x = 30 - x - x     cm, which is same as 30 - 2x    cm

(ii) Given the ratio Height : Width = 8 : 5
Since we can express the height of the letter in terms of x, we shall try to express the width of the letter in terms of x, too.


Refer to the line (in orange), width = 3 + x     cm

Now, with these information, we use the ratio to form the equation and use it to find x:


(iii) To find the perimeter of the letter, we need to find the (marked out in the diagram)








Saturday, 30 September 2017

6 AM Quiz #13: A & A

Click HERE To attempt the Quiz.
  • Click HERE to view responses
Answer scoreBonus score
Q11-
Q221
Q3(i)22
Q3(ii) optional21



Quick reference to the Questions









Suggested Solution (updated: 3 October 2017)


It's Mensuration! It's Geometry! It's Amazing!