1. In the course of

**solving the equation**, 3(1 + 2x) - (5 + x) = 10 + x

(with answer, x = 3)

we recapped:

- Expansion, Distributive Law
- Vocabulary: Like Terms, Constant, Coefficient
- Concept: Balancing equation

2. With a

**quadratic equation**, we will move all the terms to the LHS of the equation to see if it is possible to factorise the terms.

E.g. Solve x^2 = 81

By moving the terms to the LHS of the equation and factorising them,

we get (x + 9)(x - 9) = 0

By reasoning, the equation is valid when (x + 9) or (x - 9) is zero.

Hence, rewrite as

x + 9 = 0 and x - 9 = 0

From there, we solve to get x = -9 or x = 9.

3. Study Notes for Equations is given.

- Discussion of Example 1 (p4) - selected questions
- Discussion of Class Work 2 (p5) - selected questions

4. Homework

- Class Work 2 (p5) - Remaining questions - to be completed as Homework (Review), as instructed in the Google Classroom [estimated duration: 10 min]

[Flipped Learning]

- Class Work 4 (p9) has been assigned as a Homework (Diagnostic) - attempt as instructed.
- Watch the following video clips (It's a playlist with 5 examples) [estimated duration: 30 min]

*[New!] Factorial*We spent about 10 minutes to discuss what factorial is about...

1! = 1

2! = 1 x 2

8! = 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8

Hence, if we have 9! / 9!, we will get 1

If we have 9! / 8!, we will get 9

If we have 9! / 10!, we will get 1/100 or 0.01

Using the above, attempt the following without the use of calculator

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